Industrial shock absorber · Case I7 · Swinging mass with torque
Rotary actuator swing arm: which shock absorber?
Swing arm, J = 10 kg·m², still driven at 50 N·m. Watch the 39-second explainer, check the calculation, then open the same example in ImpactCal and change it to your own machine.
Inputs (SI units)
| Inertia J | 10 kg·m² |
| Speed ω | 2 rad/s |
| Torque M | 50 N·m |
| Torque radius r | 0.4 m |
| Absorber radius R | 0.6 m |
| Cycles C | 100 /h |
Calculation
| Kinetic energyE1 = ½·J·ω² = ½·10·2² | 20 J |
| Impact velocityv = ω·R = 2·0.6 | 1.2 m/s |
| Drive energyE2 = (M / r)·s = (50 / 0.4)·0.050 | 6.25 J |
| Energy per cycleE3 = E1 + E2 | 26.3 J |
| Energy per hourE4 = E3·C = 26.3·100 | 2 625 J/h |
| Effective massme = 2·E3 / v² | 36.5 kg |
s = stroke of the selected model · g = 9.81 m/s²
ImpactCal selection

AC-20-50
Best-centred utilisation
Stroke50 mm
Stopping force656 N
Deceleration18.0 m/s²
Stopping time0.104 s