Gravity chute and inclined ramp: which shock absorber?

300 kg crate slides down a 20° ramp at 1.0 m/s. Watch the 39-second explainer, check the calculation, then open the same example in ImpactCal and change it to your own machine.

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Inputs (SI units)

Mass m	300 kg
Velocity v	1.0 m/s
Angle β	20°
Friction μ	0.1
Cycles C	60 /h

Calculation

Kinetic energyE1 = ½·m·v² = ½·300·1.0²	150 J
Drive forceF = m·g·sinβ = 300·9.81·0.342	1 007 N
Drive energyE2 = F·s = 1 007·0.025	25.2 J
Energy per cycleE3 = E1 + E2	175.2 J
Energy per hourE4 = E3·C = 175.2·60	10 510 J/h
Effective massme = 2·E3 / v²	350 kg

s = stroke of the selected model · g = 9.81 m/s²

ImpactCal selection

AC-42-25

Best-centred utilisation

Stroke25 mm

Stopping force8.76 kN

Deceleration25.0 m/s²

Stopping time0.063 s

Open this example in ImpactCalSize my own application