Industrial shock absorber · Case I11 · Swinging arm with torque
Motorised boom barrier: which shock absorber?
40 kg boom, 60 N·m drive, 1.5 m/s at the stop. Watch the 39-second explainer, check the calculation, then open the same example in ImpactCal and change it to your own machine.
Inputs (SI units)
| Mass m | 40 kg |
| Velocity v | 1.5 m/s |
| Torque M | 60 N·m |
| Torque radius r | 0.5 m |
| Cycles C | 200 /h |
Calculation
| Kinetic energyE1 = m·v²/6 = 40·1.5²/6 | 15 J |
| Drive energyE2 = (M / r)·s = (60 / 0.5)·0.020 | 2.4 J |
| Energy per cycleE3 = E1 + E2 | 17.4 J |
| Energy per hourE4 = E3·C = 17.4·200 | 3 480 J/h |
| Effective massme = 2·E3 / v² | 15.5 kg |
s = stroke of the selected model · g = 9.81 m/s²
ImpactCal selection

AC-20-20
Best-centred utilisation
Stroke20 mm
Stopping force1.09 kN
Deceleration70.3 m/s²
Stopping time0.033 s